Hackerrank - Bigger is Greater Solution
Lexicographical order is often known as alphabetical order when dealing with strings. A string is greater than another string if it comes later in a lexicographically sorted list.
Given a word, create a new word by swapping some or all of its characters. This new word must meet two criteria:
- It must be greater than the original word
- It must be the smallest word that meets the first condition
For example, given the word , the next largest word is .
Complete the function biggerIsGreater below to create and return the new string meeting the criteria. If it is not possible, return
Complete the biggerIsGreater function in the editor below. It should return the smallest lexicographically higher string possible from the given string or
biggerIsGreater has the following parameter(s):
- w: a string
The first line of input contains , the number of test cases.
Each of the next lines contains .
- will contain only letters in the range ascii[a..z].
For each test case, output the string meeting the criteria. If no answer exists, print
Sample Input 0
5 ab bb hefg dhck dkhc
Sample Output 0
ba no answer hegf dhkc hcdk
- Test case 1:
bais the only string which can be made by rearranging
ab. It is greater.
- Test case 2:
It is not possible to rearrange
bband get a greater string.
- Test case 3:
hegfis the next string greater than
- Test case 4:
dhkcis the next string greater than
- Test case 5:
hcdkis the next string greater than
Sample Input 1
6 lmno dcba dcbb abdc abcd fedcbabcd
Sample Output 1
lmon no answer no answer acbd abdc fedcbabdc
Solution in Python
def biggerIsGreater(w): arr = list(w) # Find non-increasing suffix i = len(arr) - 1 while i > 0 and arr[i - 1] >= arr[i]: i -= 1 if i <= 0: return "no answer" # Find successor to pivot j = len(arr) - 1 while arr[j] <= arr[i - 1]: j -= 1 arr[i - 1], arr[j] = arr[j], arr[i - 1] # Reverse suffix arr[i : ] = arr[len(arr) - 1 : i - 1 : -1] return "".join(arr) for _ in range(int(input())): print(biggerIsGreater(input()))