Hackerrank Input and Output Solution
Objective
In this challenge, we're practicing reading input from stdin and printing output to stdout.
In C++, you can read a single whitespace-separated token of input using cin, and print output to stdout using cout. For example, let's say we declare the following variables:string s;int n;
and we want to use cin to read the input "High 5" from stdin. We can do this with the following code:cin >> s >> n;
The above code reads the first word ("High") from stdin and saves it as string , then reads the second word ("") from stdin and saves it as integer . If we want to print these values to stdout, we write the following code:cout << s << " " << n << endl;
The above code prints the contents of string , which is the word "High". Then it prints a single space (), followed by the contents of integer . Because we also want to ensure that nothing else is printed on this line, we end our line of output with a newline via endl. This results in the following output:
High 5
Task
Read numbers from stdin and print their sum to stdout.
Note: If you plan on completing this challenge in C instead of C++, you'll need to use format specifiers with printf and scanf.
Input Format
A single line containing space-separated integers: , , and .
Constraints
Output Format
Print the sum of the three numbers on a single line.
Sample Input
1 2 7
Sample Output
10
Explanation
The sum of the three numbers is .
Solution in cpp
Approach 1.
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
int x,y,z;
cin>>x>>y>>z;
cout<<x+y+z;
return 0;
}
Approach 2.
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
int a,b,c,sum=0;
cin>>a>>b>>c;
sum=a+b+c;
cout<<sum;
return 0;
}
Approach 3.
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
int a,b,c;
cin>>a>>b>>c;
int sum=a+b+c;
cout<<sum <<endl;
return 0;
}