# Hackerrank - itertools.product() Solution

This tool computes the cartesian product of input iterables.

It is equivalent to nested *for-loops*.

For example, `product(A, B)`

returns the same as `((x,y) for x in A for y in B)`

.

_{Sample Code}

```
>>> from itertools import product
>>>
>>> print list(product([1,2,3],repeat = 2))
[(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3)]
>>>
>>> print list(product([1,2,3],[3,4]))
[(1, 3), (1, 4), (2, 3), (2, 4), (3, 3), (3, 4)]
>>>
>>> A = [[1,2,3],[3,4,5]]
>>> print list(product(*A))
[(1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5), (3, 3), (3, 4), (3, 5)]
>>>
>>> B = [[1,2,3],[3,4,5],[7,8]]
>>> print list(product(*B))
[(1, 3, 7), (1, 3, 8), (1, 4, 7), (1, 4, 8), (1, 5, 7), (1, 5, 8), (2, 3, 7), (2, 3, 8), (2, 4, 7), (2, 4, 8), (2, 5, 7), (2, 5, 8), (3, 3, 7), (3, 3, 8), (3, 4, 7), (3, 4, 8), (3, 5, 7), (3, 5, 8)]
```

**Task**

You are given a two lists and . Your task is to compute their cartesian product X.

_{Example}

```
A = [1, 2]
B = [3, 4]
AxB = [(1, 3), (1, 4), (2, 3), (2, 4)]
```

**Note**: and are sorted lists, and the cartesian product's tuples should be output in sorted order.

**Input Format**

The first line contains the space separated elements of list .

The second line contains the space separated elements of list .

Both lists have no duplicate integer elements.

**Constraints**

**Output Format**

Output the space separated tuples of the cartesian product.

**Sample Input**

```
1 2
3 4
```

**Sample Output**

` (1, 3) (1, 4) (2, 3) (2, 4)`

### Solution in Python

```
from itertools import product
A= map(int,input().split())
B= map(int,input().split())
print(*product(A,B))
```