Hackerrank Java Exception Handling (Try-catch) Solution
1 min read

Hackerrank Java Exception Handling (Try-catch) Solution

Hackerrank Java Exception Handling (Try-catch) Solution

Exception handling is the process of responding to the occurrence, during computation, of exceptions – anomalous or exceptional conditions requiring special processing – often changing the normal flow of program execution. (Wikipedia)


Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs.

This problem will test your knowledge on try-catch block.

You will be given two integers  and  as input, you have to compute . If  and  are not  bit signed integers or if  is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.

Sample Input 0:

10
3

Sample Output 0:

3

Sample Input 1:

10
Hello

Sample Output 1:

java.util.InputMismatchException

Sample Input 2:

10
0

Sample Output 2:

java.lang.ArithmeticException: / by zero

Sample Input 3:

23.323
0

Sample Output 3:

java.util.InputMismatchException

Solution in java8

Approach 1.

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        try (Scanner s = new Scanner(System.in)) {

            int x = s.nextInt();
            int y = s.nextInt();

            System.out.println(x / y);
        } catch (InputMismatchException e) { 
            System.out.println(e.getClass().getName());
        } catch (ArithmeticException e) {
            System.out.println(e);
        }
    }
}

Approach 2.

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        try {
            int x = in.nextInt();
            int y = in.nextInt();
            System.out.printf("%d\n", x/y);
        } catch (InputMismatchException e) {
            System.out.println("java.util.InputMismatchException")            ;
        } catch (Exception e) {
            System.out.println(e);
        }
    }
}

Approach 3.

import java.io.*;
import java.util.*;

public class Solution {

   public static void main(String[] args) {
    	Scanner scan = new Scanner(System.in);
        try {
            int x = scan.nextInt();
            int y = scan.nextInt();
            System.out.println(x/y);
        } catch (InputMismatchException e) {
            System.out.println(e.getClass().getName());
        } catch (ArithmeticException e) {
            System.out.println(e.getClass().getName() + ": / by zero");
        }
    }
}

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