Hackerrank Java If-Else Solution

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

_{Source: Wikipedia}

Task
Given an integer, , perform the following conditional actions:

• If  is odd, print Weird
• If  is even and in the inclusive range of  to , print Not Weird
• If  is even and in the inclusive range of  to , print Weird
• If  is even and greater than , print Not Weird

Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, .

Constraints

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0:  
is odd and odd numbers are weird, so we print Weird.

Sample Case 1:  
and  is even, so it isn't weird. Thus, we print Not Weird.

Solution in java8

Approach 1.

    import java.io.*;
    import java.util.*;
    import java.text.*;
    import java.math.*;
    import java.util.regex.*;

    public class Solution {

        public static void main(String[] args) {
            Scanner sc=new Scanner(System.in);
            int n = sc.nextInt();
            System.out.println((n%2==1 || (n>=6 && n<=20)) ? "Weird" : ((n>=2 && n <=5) || n > 20) ? "Not Weird" : "Weird");
            
        }
    }

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Approach 2.

    import java.io.*;
    import java.util.*;
    import java.text.*;
    import java.math.*;
    import java.util.regex.*;


 public class Solution {

    public static void main(String[] args) {

        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();            
        String ans="";
        if(n%2==1||n%2==0&& n>5 && n<21){
          ans = "Weird";
        }
        else{

           if(n%2==0&& n>1 && n<6||n>20){
          ans = "Not Weird";
        }

        }
        System.out.println(ans);

    }
}

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Approach 3.

    import java.io.*;
    import java.util.*;
    import java.text.*;
    import java.math.*;
    import java.util.regex.*;

    public class Solution {

        public static void main(String[] args) {

            Scanner sc=new Scanner(System.in);
            int n=sc.nextInt();            
            String ans="";
            if(n%2==1){
              ans = "Weird";
            } else if (n>=2 && n <= 5){
                ans = "Not Weird";
            } else if (n>=6 && n <= 20) {
                ans = "Weird";
            } else {
                ans = "Not Weird";
            }
            System.out.println(ans);
        }
    }

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