Hackerrank Java Output Formatting Solution
1 min read

Hackerrank Java Output Formatting Solution

Hackerrank Java Output Formatting Solution

Java's System.out.printf function can be used to print formatted output. The purpose of this exercise is to test your understanding of formatting output using printf.

To get you started, a portion of the solution is provided for you in the editor; you must format and print the input to complete the solution.

Input Format

Every line of input will contain a String followed by an integer.
Each String will have a maximum of  alphabetic characters, and each integer will be in the inclusive range from  to .

Output Format

In each line of output there should be two columns:
The first column contains the String and is left justified using exactly  characters.
The second column contains the integer, expressed in exactly  digits; if the original input has less than three digits, you must pad your output's leading digits with zeroes.

Sample Input

java 100
cpp 65
python 50

Sample Output

================================
java           100 
cpp            065 
python         050 
================================

Explanation

Each String is left-justified with trailing whitespace through the first  characters. The leading digit of the integer is the  character, and each integer that was less than  digits now has leading zeroes.

Solution in java8

Approach 1.

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
            Scanner sc=new Scanner(System.in);
            System.out.println("================================");
            for(int i=0;i<3;i++)
            {
                String s1=sc.next();
                int x=sc.nextInt();
                System.out.printf("%-15s%03d%n",s1,x);
            }
            System.out.println("================================");

    }
}

Approach 2.

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
            Scanner sc=new Scanner(System.in);
            System.out.println("================================");
            for(int i=0;i<3;i++)
            {
                String s1=sc.next();
                int x=sc.nextInt();
                System.out.printf("%-15s%03d%n", s1, x);
            }
            System.out.println("================================");

    }
}

Approach 3.

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
            Scanner sc=new Scanner(System.in);
            System.out.println("================================");
            for(int i=0;i<3;i++)
            {
                String s1=sc.next();
                int x=sc.nextInt();
                System.out.printf("%-15s%03d%n", s1, x); 
            }
            System.out.println("================================");

    }
}

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