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## Hackerrank Java Strings Introduction Solution

Beeze Aal
"A string is traditionally a sequence of characters, either as a literal constant or as some kind of variable." — Wikipedia: String (computer science)

This exercise is to test your understanding of Java Strings. A sample String declaration:

String myString = "Hello World!"


The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.

Given two strings of lowercase English letters,  and , perform the following operations:

1. Sum the lengths of  and .
2. Determine if  is lexicographically larger than  (i.e.: does  come before  in the dictionary?).
3. Capitalize the first letter in  and  and print them on a single line, separated by a space.

Input Format

The first line contains a string . The second line contains another string . The strings are comprised of only lowercase English letters.

Output Format.

There are three lines of output:
For the first line, sum the lengths of  and .
For the second line, write Yes if  is lexicographically greater than  otherwise print No instead.
For the third line, capitalize the first letter in both  and  and print them on a single line, separated by a space.

Sample Input 0.

hellojava

Sample Output 0.

9
No
Hello Java

Explanation 0.

String  is "hello" and  is "java".

has a length of , and  has a length of ; the sum of their lengths is .
When sorted alphabetically/lexicographically, "hello" precedes "java"; therefore,  is not greater than  and the answer is No.

When you capitalize the first letter of both  and  and then print them separated by a space, you get "Hello Java".

### Solution in java8

Approach 1.

import java.io.*;
import java.util.*;

public class Solution {

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);
String A=sc.next();
String B=sc.next();

/* Enter your code here. Print output to STDOUT. */
System.out.println(A.length()+B.length());
System.out.println( A.compareTo(B)>0 ? "Yes" : "No" );
System.out.println( A.substring(0,1).toUpperCase()+A.substring(1,A.length())+" "+B.substring(0,1).toUpperCase()+B.substring(1,B.length()) );

}
}


Approach 2.

import java.io.*;
import java.util.*;

public class Solution {

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);
String A=sc.next();
String B=sc.next();
int x=A.length()+B.length();
System.out.println(x);
int y=A.compareTo(B);
if(y>0)
System.out.println("Yes");
else
System.out.println("No");

String ab=A.substring(0,1).toUpperCase();
String ab1=B.substring(0,1).toUpperCase();
System.out.println(ab+A.substring(1)+" "+ab1+B.substring(1));
}
}


Approach 3.

import java.io.*;
import java.util.*;

public class Solution {

public static String AIsLarger(String A, String B) {
return A.compareTo(B) > 0 ? "Yes" : "No";
}

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);
String A=sc.next();
String B=sc.next();

/* Enter your code here. Print output to STDOUT. */
System.out.println((A.length() + B.length()));
System.out.println(AIsLarger(A, B));

System.out.println(A.substring(0, 1).toUpperCase() + A.substring(1) + " " + B.substring(0, 1).toUpperCase() + B.substring(1));

}
}