# Hackerrank - Largest Permutation Solution

You are given an unordered array of unique integers incrementing from . You can swap any two elements a limited number of times. Determine the largest lexicographical value array that can be created by executing no more than the limited number of swaps.

For example, if and the maximum swaps , the following arrays can be formed by swapping the with the other elements:[2,1,3,4][3,2,1,4][4,2,3,1]

The highest value of the four (including the original) is . If , we can swap to the highest possible value: .

**Function Description**

Complete the *largestPermutation* function in the editor below. It must return an array that represents the highest value permutation that can be formed.

largestPermutation has the following parameter(s):

*k*: an integer that represents the limit of swaps*arr*: an array of integers

**Input Format**

The first line contains two space-separated integers and , the length of and the maximum swaps that can be performed. The second line contains unique space-separated integers where .

**Constraints**

**Output Format**

Print the lexicographically largest permutation you can make with **at most** swaps.**Sample Input 0**

```
5 1
4 2 3 5 1
```

**Sample Output 0**

```
5 2 3 4 1
```

**Explanation 0**

You can swap any two numbers in and see the largest permutation is

**Sample Input 1**

```
3 1
2 1 3
```

**Sample Output 1**

```
3 1 2
```

**Explanation 1**

With 1 swap we can get , and . Of these, is the largest permutation.

**Sample Input 2**

```
2 1
2 1
```

**Sample Output 2**

```
2 1
```

**Explanation 2**

We can see that is already the largest permutation. We don't make any swaps.

### Solution in Python

```
def largestPermutation(k, arr):
a = dict(enumerate(arr))
b = {v:k for k,v in a.items()}
l = len(arr)
for i in range(l):
if k and a[i]!=l-i:
x = a[i]
y = b[l-i]
a[i] = l-i
a[y] = x
b[x] = y
k-=1
yield a[i]
n,k = map(int,input().split())
arr = list(map(int,input().split()))
print(*largestPermutation(k, arr))
```