Hackerrank - Library Fine Solution
Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:
- If the book is returned on or before the expected return date, no fine will be charged (i.e.: .
- If the book is returned after the expected return day but still within the same calendar month and year as the expected return date, .
- If the book is returned after the expected return month but still within the same calendar year as the expected return date, the .
- If the book is returned after the calendar year in which it was expected, there is a fixed fine of .
Charges are based only on the least precise measure of lateness. For example, whether a book is due January 1, 2017 or December 31, 2017, if it is returned January 1, 2018, that is a year late and the fine would be .
Function Description
Complete the libraryFine function in the editor below. It must return an integer representing the fine due.
libraryFine has the following parameter(s):
- d1, m1, y1: returned date day, month and year
- d2, m2, y2: due date day, month and year
Input Format
The first line contains space-separated integers, , denoting the respective , , and on which the book was returned.
The second line contains space-separated integers, , denoting the respective , , and on which the book was due to be returned.
Constraints
Output Format
Print a single integer denoting the library fine for the book received as input.
Sample Input
9 6 2015
6 6 2015
Sample Output
45
Explanation
Given the following dates:
Returned: d1=9, m1=6, y1=2015
Due: d2=6, m2=6,y2=2015
Because y2=y1, we know it is less than a year late.
Because m2=m1, we know it's less than a month late.
Because d2<d1, we know that it was returned late (but still within the same month and year).
Per the library's fee structure, we know that our fine will be . We then print the result of as our output.
Solution in Python
def libraryFine(d1,m1,y1,d2,m2,y2):
if y1>y2:
#if year of return is greater than year due
return 10000
elif m1>m2 and y1==y2:
#if returned in the same year and month of return is greater than month due
return (m1-m2)*500
elif d1>d2 and y1==y2 and m1==m2:
#if returned in the same year and month, and the date of return is greater than due date
return (d1-d2)*15
else:
return 0
d1,m1,y1 = map(int,input().split())
d2,m2,y2 = map(int,input().split())
print(libraryFine(d1,m1,y1,d2,m2,y2))