## Hackerrank - Library Fine Solution

Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:

- If the book is returned on or before the expected return date, no fine will be charged (i.e.: .
- If the book is returned after the expected return
*day*but still within the same calendar month and year as the expected return date, . - If the book is returned after the expected return
*month*but still within the same calendar year as the expected return date, the . - If the book is returned after the calendar
*year*in which it was expected, there is a fixed fine of .

Charges are based only on the least precise measure of lateness. For example, whether a book is due January 1, 2017 or December 31, 2017, if it is returned January 1, 2018, that is a year late and the fine would be .

**Function Description**

Complete the *libraryFine* function in the editor below. It must return an integer representing the fine due.

libraryFine has the following parameter(s):

*d1, m1, y1*: returned date day, month and year*d2, m2, y2*: due date day, month and year

**Input Format**

The first line contains space-separated integers, , denoting the respective , , and on which the book was returned.

The second line contains space-separated integers, , denoting the respective , , and on which the book was due to be returned.

**Constraints**

**Output Format**

Print a single integer denoting the library fine for the book received as input.

**Sample Input**

```
9 6 2015
6 6 2015
```

**Sample Output**

```
45
```

**Explanation**

Given the following dates:

Returned: d1=9, m1=6, y1=2015

Due: d2=6, m2=6,y2=2015

Because y2=y1, we know it is less than a year late.

Because m2=m1, we know it's less than a month late.

Because d2<d1, we know that it was returned late (but still within the same month and year).

Per the library's fee structure, we know that our fine will be . We then print the result of as our output.

### Solution in Python

```
def libraryFine(d1,m1,y1,d2,m2,y2):
if y1>y2:
#if year of return is greater than year due
return 10000
elif m1>m2 and y1==y2:
#if returned in the same year and month of return is greater than month due
return (m1-m2)*500
elif d1>d2 and y1==y2 and m1==m2:
#if returned in the same year and month, and the date of return is greater than due date
return (d1-d2)*15
else:
return 0
d1,m1,y1 = map(int,input().split())
d2,m2,y2 = map(int,input().split())
print(libraryFine(d1,m1,y1,d2,m2,y2))
```