Hackerrank - Library Fine Solution
2 min read

Hackerrank - Library Fine Solution

Hackerrank - Library Fine Solution

Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:

  1. If the book is returned on or before the expected return date, no fine will be charged (i.e.: .
  2. If the book is returned after the expected return day but still within the same calendar month and year as the expected return date, .
  3. If the book is returned after the expected return month but still within the same calendar year as the expected return date, the .
  4. If the book is returned after the calendar year in which it was expected, there is a fixed fine of .

Charges are based only on the least precise measure of lateness. For example, whether a book is due January 1, 2017 or December 31, 2017, if it is returned January 1, 2018, that is a year late and the fine would be .

Function Description

Complete the libraryFine function in the editor below. It must return an integer representing the fine due.

libraryFine has the following parameter(s):

  • d1, m1, y1: returned date day, month and year
  • d2, m2, y2: due date day, month and year

Input Format

The first line contains  space-separated integers, , denoting the respective , , and  on which the book was returned.
The second line contains  space-separated integers, , denoting the respective , , and  on which the book was due to be returned.

Constraints

Output Format

Print a single integer denoting the library fine for the book received as input.

Sample Input

9 6 2015
6 6 2015

Sample Output

45

Explanation

Given the following dates:
Returned: d1=9, m1=6, y1=2015
Due: d2=6, m2=6,y2=2015

Because y2=y1, we know it is less than a year late.
Because m2=m1, we know it's less than a month late.
Because d2<d1, we know that it was returned late (but still within the same month and year).

Per the library's fee structure, we know that our fine will be . We then print the result of  as our output.

Solution in Python

def libraryFine(d1,m1,y1,d2,m2,y2):
    if y1>y2:
    	#if year of return is greater than year due
        return 10000
    elif m1>m2 and y1==y2:
    	#if returned in the same year and month of return is greater than month due
        return (m1-m2)*500
    elif d1>d2 and y1==y2 and m1==m2:
    	#if returned in the same year and month, and the date of return is greater than due date
        return (d1-d2)*15
    else:
        return 0

d1,m1,y1 = map(int,input().split())
d2,m2,y2 = map(int,input().split())
print(libraryFine(d1,m1,y1,d2,m2,y2))

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