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## HackerRank - Merge the Tools! Solution

HackerRankDude

Consider the following:

• A string, s , of length n where s = c0c1...cn-1.
• An integer, k , where k is a factor of n.

We can split s into n/k subsegments where each subsegment, ti , consists of a contiguous block of  characters in . Then, use each  to create string  such that:

• The characters in  are a subsequence of the characters in .
• Any repeat occurrence of a character is removed from the string such that each character in  occurs exactly once. In other words, if the character at some index  in  occurs at a previous index  in , then do not include the character in string .

Given  and , print  lines where each line  denotes string .

Input Format

The first line contains a single string denoting .
The second line contains an integer, , denoting the length of each subsegment.

Constraints

• , where  is the length of
• It is guaranteed that  is a multiple of .

Output Format

Print  lines where each line  contains string .

Sample Input

AABCAAADA
3


Sample Output

AB
CA


Explanation

String  is split into  equal parts of length . We convert each  to  by removing any subsequent occurrences non-distinct characters in :

We then print each  on a new line.

## Solution in Python

def merge_the_tools(string, k):
for i in range(0,len(string), k):
#slice string upto k characters
line = string[i:i+k]
seen = set()
for i in line:
#only print if we haven't already seen this character
if i not in seen:
print(i,end="")
#prints a new line
print()

if __name__ == '__main__':
string, k = input(), int(input())
merge_the_tools(string, k)

Below solution is less efficient

def merge_the_tools(string, k):
for i in range(0,len(string), k):
line = string[i:i+k]
new = ""
for i in line:
if i not in new:
new+=i
print(new)

string, k = input(), int(input())
merge_the_tools(string, k)