HackerRank No Idea! Solution

# HackerRank No Idea! Solution

There is an array of  integers. There are also  disjoint sets,  and , each containing integers. You like all the integers in set  and dislike all the integers in set . Your initial happiness is . For each  integer in the array, if , you add  to your happiness. If , you add  to your happiness. Otherwise, your happiness does not change. Output your final happiness at the end.

Note: Since  and  are sets, they have no repeated elements. However, the array might contain duplicate elements.

Constraints

Input Format

The first line contains integers  and  separated by a space.
The second line contains  integers, the elements of the array.
The third and fourth lines contain  integers,  and , respectively.

Output Format

Output a single integer, your total happiness.

Sample Input

Sample Output

3 2
1 5 3
3 1
5 7

1


Explanation

You gain  unit of happiness for elements  and  in set . You lose  unit for  in set . The element  in set  does not exist in the array so it is not included in the calculation.

Hence, the total happiness is .

## Solution in Python3

n,m = map(int,input().split())
N = list(map(int,input().split()))
A = set(map(int,input().split()))
B = set(map(int,input().split()))
#Union set A & B
C = A | B
#Exclude all numbers which doesn't exit in both A & B
N = (i for i in N if i in C)
#Add 1 if number is in set A else subtract 1
print(sum(1 if i in A else -1 for i in N ))