You've successfully subscribed to The Poor Coder | Hackerrank Solutions
Great! Next, complete checkout for full access to The Poor Coder | Hackerrank Solutions
Welcome back! You've successfully signed in.
Success! Your account is fully activated, you now have access to all content.
HackerRank No Idea! Solution

HackerRank No Idea! Solution

HackerRankDude
HackerRankDude

There is an array of  integers. There are also  disjoint sets,  and , each containing integers. You like all the integers in set  and dislike all the integers in set . Your initial happiness is . For each  integer in the array, if , you add  to your happiness. If , you add  to your happiness. Otherwise, your happiness does not change. Output your final happiness at the end.

Note: Since  and  are sets, they have no repeated elements. However, the array might contain duplicate elements.

Constraints


Input Format

The first line contains integers  and  separated by a space.
The second line contains  integers, the elements of the array.
The third and fourth lines contain  integers,  and , respectively.

Output Format

Output a single integer, your total happiness.

Sample Input

Sample Output

3 2
1 5 3
3 1
5 7
1

Explanation

You gain  unit of happiness for elements  and  in set . You lose  unit for  in set . The element  in set  does not exist in the array so it is not included in the calculation.

Hence, the total happiness is .

Solution in Python3

n,m = map(int,input().split())
N = list(map(int,input().split()))
A = set(map(int,input().split()))
B = set(map(int,input().split()))
#Union set A & B
C = A | B
#Exclude all numbers which doesn't exit in both A & B
N = (i for i in N if i in C)
#Add 1 if number is in set A else subtract 1
print(sum(1 if i in A else -1 for i in N ))