Hackerrank Ruby - Methods - Keyword Arguments Solution

In our previous challenge, we explored one way to pass a variable number of arguments to our methods. While it may seem handy feature to have, except few circumstances, you are never going to use that many variables for your method. Also, if your are passing several different types of variables to the method which then will be assigned to the array, it can be difficult for the programmer invoking the method to remember the proper order for those arguments.

Ruby allows you to (partially) mitigate this problem by passing a Hash as an argument or one of the arguments. For example, you have a method that takes a URI to download a file and another argument containing a Hash of other named options (proxy, timeout, active-connections etc.,)def fetch_file(uri, options)    if options.has_key?(:proxy)        # do something    endend

The main problem with this technique, however, is that you cannot easily set default value for arguments (Read more). Since this construct is highly useful, Ruby 2 introduced keyword arguments which allows you to write -def foo(x, str: "foo", num: 424242)  [x, str, num]end foo(13) #=> [13, 'foo', 424242]foo(13, str: 'bar') #=> [13, 'bar', 424242]

Also, introducing the double splat (**) which similar to it's counterpart collects all the extra named keywords as a hash parameter.def foo(str: "foo", num: 424242, **options)  [str, num, options]end foo #=> ['foo', 424242, {}]foo(check: true) # => ['foo', 424242, {check: true}]

In this challenge, your task is to write a method convert_temp that helps in temperature conversion. The method will receive a number as an input (temperature), a named parameter input_scale (scale for input temperature), and an optional parameter output_scale (output temperature scale, defaults to Celsius) and return the converted temperature. It should perform interconversion between Celsius, Fahrenheit and Kelvin scale.

For example,> convert_temp(0, input_scale: 'celsius', output_scale: 'kelvin')=> 273.15 > convert_temp(0, input_scale: 'celsius', output_scale: 'fahrenheit')=> 32.0

Note that the input values are lowercase version of corresponding scales.

Solution in ruby

Approach 1.

def convert_temp(t,scales)
    
    case scales[:input_scale]
        when "kelvin"
            t-=273.15
        when "fahrenheit"
            t=(t-32)*5/9.0
    end
    
    scales[:output_scale]="celsius" if not scales.has_key?(:output_scale)
    
    case scales[:output_scale]
        when "kelvin"
            t+=273.15
        when "fahrenheit"
            t=1.8*t+32.0
    end

    return t
end

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Approach 2.

def convert_temp(temp, input_scale:, output_scale: 'Celsius')
    case input_scale.downcase
    when 'fahrenheit'
        return output_scale == 'kelvin' ? 
        ((temp - 32) / 1.8) + 273.15 : (temp - 32) / 1.8
    when 'celsius'
        return output_scale == 'kelvin' ? 
        temp + 273.15 : (temp * 1.8) + 32
    when 'kelvin'
        return output_scale == 'celsius' ? 
        temp - 273.15 : (temp - 273.15) * 1.8
    end
end

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