# Hackerrank - Text Alignment Solution

In Python, a string of text can be aligned left, right and center.

.ljust(width)

This method returns a left aligned string of length width.

>>> width = 20
>>> print 'HackerRank'.ljust(width,'-')
HackerRank----------


.center(width)

This method returns a centered string of length width.

>>> width = 20
>>> print 'HackerRank'.center(width,'-')
-----HackerRank-----


.rjust(width)

This method returns a right aligned string of length width.

>>> width = 20
>>> print 'HackerRank'.rjust(width,'-')
----------HackerRank


You are given a partial code that is used for generating the HackerRank Logo of variable thickness.
Your task is to replace the blank (______) with rjust, ljust or center.

Input Format

A single line containing the thickness value for the logo.

Constraints

The thickness must be an odd number.

Output Format

Output the desired logo.

Sample Input

5


Sample Output

    H
HHH
HHHHH
HHHHHHH
HHHHHHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHHHHHH
HHHHHHH
HHHHH
HHH
H 

### Solution in Python

thickness = int(input())
c = 'H'

#Top Cone
for i in range(thickness):
print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))

#Top Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Middle Belt
for i in range((thickness+1)//2):
print((c*thickness*5).center(thickness*6))

#Bottom Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Bottom Cone
for i in range(thickness):
print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))