# Hackerrank - Text Alignment Solution

In Python, a string of text can be aligned * left, right* and

*.*

*center***.ljust(width)**

This method returns a left aligned string of length * width*.

```
>>> width = 20
>>> print 'HackerRank'.ljust(width,'-')
HackerRank----------
```

**.center(width)**

This method returns a centered string of length * width*.

```
>>> width = 20
>>> print 'HackerRank'.center(width,'-')
-----HackerRank-----
```

**.rjust(width)**

This method returns a right aligned string of length * width*.

```
>>> width = 20
>>> print 'HackerRank'.rjust(width,'-')
----------HackerRank
```

**Task**

You are given a partial code that is used for generating the * HackerRank Logo* of variable

*.*

*thickness*Your task is to replace the blank (

`______`

) with *or*

*rjust, ljust**.*

*center***Input Format**

A single line containing the * thickness* value for the logo.

**Constraints**

The * thickness* must be an

*number.*

*odd***Output Format**

Output the desired logo.

**Sample Input**

```
5
```

**Sample Output**

```
H
HHH
HHHHH
HHHHHHH
HHHHHHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHHHHHH
HHHHHHH
HHHHH
HHH
H
```

### Solution in Python

```
thickness = int(input())
c = 'H'
#Top Cone
for i in range(thickness):
print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))
#Top Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))
#Middle Belt
for i in range((thickness+1)//2):
print((c*thickness*5).center(thickness*6))
#Bottom Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))
#Bottom Cone
for i in range(thickness):
print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))
```