Hackerrank - Words Score Solution
In this challenge, the task is to debug the existing code to successfully execute all provided test files.
Consider that vowels in the alphabet are
a, e, i, o, u and
score_words takes a list of lowercase words as an argument and returns a score as follows:
The score of a single word is if the word contains an even number of vowels. Otherwise, the score of this word is . The score for the whole list of words is the sum of scores of all words in the list.
Debug the given function
score_words such that it returns a correct score.
Your function will be tested on several cases by the locked template code.
The input is read by the provided locked code template. In the first line, there is a single integer denoting the number of words. In the second line, there are space-separated lowercase words.
- Each word has at most letters and all letters are English lowercase letters
The output is produced by the provided and locked code template. It calls function
score_words with the list of words read from the input as the argument and prints the returned score to the output.
Sample Input 0
2 hacker book
Sample Output 0
There are two words in the input:
book. The score of the word
hacker is because it contains an even number of vowels, i.e. vowels, and the score of
book is for the same reason. Thus the total score is .
Sample Input 1
3 programming is awesome
Sample Output 1
There are words in the input:
awesome. The score of
programming is since it contains vowels, an odd number of vowels. The score of
is is also because it has an odd number of vowels. The score of
awesome is since it contains vowels, an even number of vowels. Thus, the total score is .
Solution in Python
import re def is_vowel(letter): return letter in ['a', 'e', 'i', 'o', 'u', 'y'] def score_words(words): score = 0 for word in words: num_vowels = 0 for letter in word: if is_vowel(letter): num_vowels += 1 if num_vowels % 2 == 0: score += 2 else: score += 1 return score n = int(input()) words = input().split() print(score_words(words))
import re def score_words(words): score = 0 for word in words: score+= len(re.findall("[aeiouy]",word))%2 or 2 return score n = int(input()) words = input().split() print(score_words(words))