# Leetcode - Create Target Array in the Given Order Solution

Given two arrays of integers `nums`

and `index`

. Your task is to create *target* array under the following rules:

- Initially
*target*array is empty. - From left to right read nums[i] and index[i], insert at index
`index[i]`

the value`nums[i]`

in*target*array. - Repeat the previous step until there are no elements to read in
`nums`

and`index.`

Return the *target* array.

It is guaranteed that the insertion operations will be valid.

**Example 1:**

```
Input: nums = [0,1,2,3,4], index = [0,1,2,2,1]
Output: [0,4,1,3,2]
Explanation:
nums index target
0 0 [0]
1 1 [0,1]
2 2 [0,1,2]
3 2 [0,1,3,2]
4 1 [0,4,1,3,2]
```

**Example 2:**

```
Input: nums = [1,2,3,4,0], index = [0,1,2,3,0]
Output: [0,1,2,3,4]
Explanation:
nums index target
1 0 [1]
2 1 [1,2]
3 2 [1,2,3]
4 3 [1,2,3,4]
0 0 [0,1,2,3,4]
```

**Example 3:**

```
Input: nums = [1], index = [0]
Output: [1]
```

**Constraints:**

`1 <= nums.length, index.length <= 100`

`nums.length == index.length`

`0 <= nums[i] <= 100`

`0 <= index[i] <= i`

## Solution in Python

```
class Solution:
def createTargetArray(self, nums: List[int], index: List[int]) -> List[int]:
arr = []
for x,y in zip(nums,index):
arr.insert(y,x)
return arr
```