# Leetcode - Daily Temperatures Solution

Given a list of daily temperatures `T`

, return a list such that, for each day in the input, tells you how many days you would have to wait until a warmer temperature. If there is no future day for which this is possible, put `0`

instead.

For example, given the list of temperatures `T = [73, 74, 75, 71, 69, 72, 76, 73]`

, your output should be `[1, 1, 4, 2, 1, 1, 0, 0]`

.

**Note:** The length of `temperatures`

will be in the range `[1, 30000]`

. Each temperature will be an integer in the range `[30, 100]`

.

## Solution in Python

```
class Solution:
def dailyTemperatures(self, T: List[int]) -> List[int]:
output = [0]*len(T)
warmer = [300002]*102
for index,value in reversed(list(enumerate(T))):
nearest_warmer = min(warmer[i] for i in range(value+1,102))
if nearest_warmer != 300002:
output[index] = nearest_warmer-index
warmer[value] = index
return output
```