Leetcode - Long Pressed Name Solution
1 min read

Leetcode - Long Pressed Name Solution

Your friend is typing his name into a keyboard. Sometimes, when typing a character c, the key might get long pressed, and the character will be typed 1 or more times.

You examine the typed characters of the keyboard. Return True if it is possible that it was your friends name, with some characters (possibly none) being long pressed.

Example 1:

Input: name = "alex", typed = "aaleex"
Output: true
Explanation: 'a' and 'e' in 'alex' were long pressed.

Example 2:

Input: name = "saeed", typed = "ssaaedd"
Output: false
Explanation: 'e' must have been pressed twice, but it wasn't in the typed output.

Example 3:

Input: name = "leelee", typed = "lleeelee"
Output: true

Example 4:

Input: name = "laiden", typed = "laiden"
Output: true
Explanation: It's not necessary to long press any character.

Constraints:

  • 1 <= name.length <= 1000
  • 1 <= typed.length <= 1000
  • name and typed contain only lowercase English letters.

Solution in Python

from itertools import groupby
class Solution:
    def isLongPressedName(self, name: str, typed: str) -> bool:
        groupName = [(x,len(list(y))) for x,y in (groupby(name))]
        groupTyped = [(x,len(list(y))) for x,y in (groupby(typed))]
        if len(groupName)!= len(groupTyped):
            return False
        for (a,b),(x,y) in zip(groupName,groupTyped):
            if not a==x or y<b:
                return False
        return True

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