# Leetcode - Sqrt(x) Solution

Given a non-negative integer `x`

, compute and return *the square root of* `x`

.

Since the return type is an integer, the decimal digits are **truncated**, and only **the integer part** of the result is returned.

**Example 1:**

```
Input: x = 4
Output: 2
```

**Example 2:**

```
Input: x = 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.
```

**Constraints:**

`0 <= x <= 2`

^{31}- 1

## Solution in Python

```
class Solution:
def mySqrt(self, x: int) -> int:
return int(x**0.5)
```