socket getting 2 time call in server react js

There are a few different ways that you can handle a socket getting two time calls in server react.js. The first solution would be to use a simple conditional statement to check if the socket is open or not before sending a message through it. You could do this by using the

Socket.readyState

property, which will give you either a 0 (if the socket is not open) or a 1 (if the socket is open). You could wrap this in an if statement, and if the socket is not open, open it and send the message, like so:

if (socket.readyState !== 1) {
    socket.open();
    socket.send('example message');
}

Another solution would be to utilize the

onopen

event, which is triggered when the socket becomes active and ready to send data. This would allow you to send the message in the event function, like so:

socket.onopen = function() {
    socket.send('example message');
};

A third option would be to wrap the socket.send() method in a try/catch statement, as this will allow you to catch any errors that may occur when sending the message, such as if the socket is closed. The try/catch statement would look like this:

try {
    socket.send('example message);
} catch(error) {
    // handle error here
}

You could also use a timeout function to check if the socket is open or not before sending the message. This could be done by using the

setTimeout

method with a callback function that will send the message once the timeout has been reached. This would look something like this:

setTimeout(function() {
    socket.send('example message');
}, 1000); // will send message after 1 second

These are just a few different ways to handle a socket getting two time calls in server react.js. Depending on the situation you may find one solution more suitable than another, so it's important to weigh the pros and cons of each solution before making a decision.