Hackerrank - Any or All Solution
any()
This expression returns True
if any element of the iterable is true.
If the iterable is empty, it will return False
.
Code
>>> any([1>0,1==0,1<0])
True
>>> any([1<0,2<1,3<2])
False
all()
This expression returns True
if all of the elements of the iterable are true. If the iterable is empty, it will return True
.
Code
>>> all(['a'<'b','b'<'c'])
True
>>> all(['a'<'b','c'<'b'])
False
Task
You are given a space separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer.
Input Format
The first line contains an integer . is the total number of integers in the list.
The second line contains the space separated list of integers.
Constraints
Output Format
Print True
if all the conditions of the problem statement are satisfied. Otherwise, print False
.
Sample Input
5
12 9 61 5 14
Sample Output
True
Explanation
Condition 1: All the integers in the list are positive.
Condition 2: 5 is a palindromic integer.
Hence, the output is True
.
Can you solve this challenge in 3 lines of code or less
?
There is no penalty
for solutions that are correct but have more than 3 lines.
Solution in Python
x,nums =input(), input().split()
print(all(map(lambda x:int(x)>-1,nums)) and any(map(lambda x:x==x[::-1],nums)) )