## Set .discard(), .remove() & .pop() Solution

**.remove(x)**

This operation removes element from the set.

If element does not exist, it raises a ** KeyError**.

The

*.remove(x)*operation returns

**.**

`None`

**Example**>>> s = set([1, 2, 3, 4, 5, 6, 7, 8, 9]) >>> s.remove(5) >>> print s set([1, 2, 3, 4, 6, 7, 8, 9]) >>> print s.remove(4) None >>> print s set([1, 2, 3, 6, 7, 8, 9]) >>> s.remove(0) KeyError: 0

**.discard(x)**

This operation also removes element from the set.

If element does not exist, it **does not** raise a `KeyError`

.

The *.discard(x)* operation returns ** None**.

**Example**>>> s = set([1, 2, 3, 4, 5, 6, 7, 8, 9]) >>> s.discard(5) >>> print s set([1, 2, 3, 4, 6, 7, 8, 9]) >>> print s.discard(4) None >>> print s set([1, 2, 3, 6, 7, 8, 9]) >>> s.discard(0) >>> print s set([1, 2, 3, 6, 7, 8, 9])

**.pop()**

This operation removes and return an arbitrary element from the set.

If there are no elements to remove, it raises a ** KeyError**.

**Example**>>> s = set([1]) >>> print s.pop() 1 >>> print s set([]) >>> print s.pop() KeyError: pop from an empty set

**Task**

You have a non-empty set , and you have to execute commands given in lines.

The commands will be *pop, remove* and *discard*.

**Input Format**

The first line contains integer , the number of elements in the set .

The second line contains space separated elements of set . All of the elements are non-negative integers, less than or equal to 9.

The third line contains integer , the number of commands.

The next lines contains either *pop, remove* and/or *discard* commands followed by their associated value.

**Constraints**

**Output Format**

Print the sum of the elements of set on a single line.

**Sample Input**

```
9
1 2 3 4 5 6 7 8 9
10
pop
remove 9
discard 9
discard 8
remove 7
pop
discard 6
remove 5
pop
discard 5
```

**Sample Output**

```
4
```

**Explanation**

After completing these operations on the set, we get *set([4])*. Hence, the sum is .

**Note**: Convert the elements of set *s* to *integers* while you are assigning them. To ensure the proper input of the set, we have added the first two lines of code to the editor.

### Solution in Python

```
n = int(input())
s = set(map(int, input().split()))
d = {"pop":s.pop, "remove":s.remove, "discard": s.discard}
for _ in range(int(input())):
c = input().split()
d[c[0]](int(c[1])) if len(c)>1 else d[c[0]]()
print(sum(s))
```

Explanation

What I actually did is bind those 3 words to their respective functions for the list *s *and then store it in a dictionary.

Now these values will become equal

```
>>> d["pop"]==s.pop
True
>>> d["remove"]==s.remove
True
>>> d["discard"]==s.discard
True
```

If a user enters

`remove 5`

Both of the following will perform our desired action

```
d["remove"](int("5"))
s.remove(5)
```

So we take input from the user and perform the action using d instead of s

```
>>> c = input().split()
["remove", "5"]
>>> c[0] == "remove"
True
>>> c[1] == "5
True
```

When c[1] is blank len of c will be 1 in such case we call our function without any parameter. Hence our code can be written like this

`d[c[0]](int(c[1])) if len(c)>1 else d[c[0]]()`

Or this

```
if len(c)>1:
d[c[0]](int(c[1]))
else:
d[c[0]]()
```

And that's it! Hope it helped you understand clearly.