## Hackerrank - Symmetric Difference Solution

**Objective**

Today, we're learning about a new data type: *sets*.

**Concept**

If the inputs are given on one line separated by a space character, use *split()* to get the separate values in the form of a list:

```
>> a = raw_input()
5 4 3 2
>> lis = a.split()
>> print (lis)
['5', '4', '3', '2']
```

If the list values are all integer types, use the *map()* method to convert all the strings to integers.

```
>> newlis = list(map(int, lis))
>> print (newlis)
[5, 4, 3, 2]
```

Sets are an unordered bag of unique values. A single set contains values of any immutable data type.**CREATING SETS**

```
>> myset = {1, 2} # Directly assigning values to a set
>> myset = set() # Initializing a set
>> myset = set(['a', 'b']) # Creating a set from a list
>> myset
{'a', 'b'}
```

**MODIFYING SETS**

Using the *add()* function:

```
>> myset.add('c')
>> myset
{'a', 'c', 'b'}
>> myset.add('a') # As 'a' already exists in the set, nothing happens
>> myset.add((5, 4))
>> myset
{'a', 'c', 'b', (5, 4)}
```

Using the *update()* function:

```
>> myset.update([1, 2, 3, 4]) # update() only works for iterable objects
>> myset
{'a', 1, 'c', 'b', 4, 2, (5, 4), 3}
>> myset.update({1, 7, 8})
>> myset
{'a', 1, 'c', 'b', 4, 7, 8, 2, (5, 4), 3}
>> myset.update({1, 6}, [5, 13])
>> myset
{'a', 1, 'c', 'b', 4, 5, 6, 7, 8, 2, (5, 4), 13, 3}
```

**REMOVING ITEMS**

Both the *discard()* and *remove()* functions take a single value as an argument and removes that value from the set. If that value is not present, *discard()* does nothing, but *remove()* will raise a KeyError exception.

```
>> myset.discard(10)
>> myset
{'a', 1, 'c', 'b', 4, 5, 7, 8, 2, 12, (5, 4), 13, 11, 3}
>> myset.remove(13)
>> myset
{'a', 1, 'c', 'b', 4, 5, 7, 8, 2, 12, (5, 4), 11, 3}
```

** COMMON SET OPERATIONS** Using

*union()*,

*intersection()*and

*difference()*functions.

```
>> a = {2, 4, 5, 9}
>> b = {2, 4, 11, 12}
>> a.union(b) # Values which exist in a or b
{2, 4, 5, 9, 11, 12}
>> a.intersection(b) # Values which exist in a and b
{2, 4}
>> a.difference(b) # Values which exist in a but not in b
{9, 5}
```

The *union()* and *intersection()* functions are symmetric methods:

```
>> a.union(b) == b.union(a)
True
>> a.intersection(b) == b.intersection(a)
True
>> a.difference(b) == b.difference(a)
False
```

These other built-in data structures in Python are also useful.

**Task**

Given sets of integers, and , print their symmetric difference in ascending order. The term *symmetric difference* indicates those values that exist in either or but do not exist in both.

**Input Format**

The first line of input contains an integer, .

The second line contains space-separated integers.

The third line contains an integer, .

The fourth line contains space-separated integers.

**Output Format**

Output the symmetric difference integers in ascending order, one per line.

**Sample Input**

```
4
2 4 5 9
4
2 4 11 12
```

**Sample Output**

```
5
9
11
12
```

### Solution in Python

```
input()
m = set(map(int,input().split()))
input()
n = set(map(int,input().split()))
print(*sorted(m^n), sep="\n")
```