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Hackerrank - Grading Students
Solution

Hackerrank - Grading Students Solution

Beeze Aal
Beeze Aal

HackerLand University has the following grading policy:

  • Every student receives a ¬†in the inclusive range from ¬†to .
  • Any ¬†less than ¬†is a failing grade.

Sam is a professor at the university and likes to round each student's  according to these rules:

  • If the difference between the ¬†and the next multiple of ¬†is less than , round ¬†up to the next multiple of .
  • If the value of ¬†is less than , no rounding occurs as the result will still be a failing grade.

For example,  will be rounded to  but  will not be rounded because the rounding would result in a number that is less than .

Given the initial value of  for each of Sam's  students, write code to automate the rounding process.

Function Description

Complete the function gradingStudents in the editor below. It should return an integer array consisting of rounded grades.

gradingStudents has the following parameter(s):

  • grades: an array of integers representing grades before rounding

Input Format

The first line contains a single integer, , the number of students.
Each line  of the  subsequent lines contains a single integer, , denoting student 's grade.

Constraints

Output Format

For each , print the rounded grade on a new line.

Sample Input 0

4
73
67
38
33

Sample Output 0

75
67
40
33

Explanation 0

image
  1. Student  received a , and the next multiple of  from  is . Since , the student's grade is rounded to .
  2. Student  received a , and the next multiple of  from  is . Since , the grade will not be modified and the student's final grade is .
  3. Student  received a , and the next multiple of  from  is . Since , the student's grade will be rounded to .
  4. Student  received a grade below , so the grade will not be modified and the student's final grade is .

Solution in Python

for _ in range(int(input())):
    x = int(input())
    x = x-x%5+5 if x%5>2 and x>=38 else x
    print(x)