## Hackerrank - Sequence Equation Solution

Given a sequence of integers, where each element is distinct and satisfies . For *each* where , find any integer such that and print the value of on a new line.

For example, assume the sequence . Each value of between and , the length of the sequence, is analyzed as follows:

- , so
- , so
- , so
- , so
- , so

The values for are .

**Function Description**

Complete the *permutationEquation* function in the editor below. It should return an array of integers that represent the values of .

permutationEquation has the following parameter(s):

*p*: an array of integers

**Input Format**

The first line contains an integer , the number of elements in the sequence.

The second line contains space-separated integers where .

**Constraints**

- , where .
- Each element in the sequence is distinct.

**Output Format**

For each from to , print an integer denoting any valid satisfying the equation on a new line.

**Sample Input 0**

```
3
2 3 1
```

**Sample Output 0**

```
2
3
1
```

**Explanation 0**

Given the values of , , and , we calculate and print the following values for each from to :

- , so we print the value of on a new line.
- , so we print the value of on a new line.
- , so we print the value of on a new line.

**Sample Input 1**

```
5
4 3 5 1 2
```

**Sample Output 1**

```
1
3
5
4
2
```

### Solution in Python

```
from collections import defaultdict
d1= defaultdict(int)
n = int(input())
a = list(map(int,input().split()))
for x,y in enumerate(a,1):
d1[x]=y
d2 = {v:k for k,v in d1.items()}
for x,y in sorted(d1.items(), key=lambda k_v:k_v[1]):
print(d2[x])
```