Hackerrank Minimum Loss Solution
9 min read

Hackerrank Minimum Loss Solution

Hackerrank Minimum Loss Solution

.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue} .MathJax_SVG_LineBox {display: table!important} .MathJax_SVG_LineBox span {display: table-cell!important; width: 10000em!important; min-width: 0; max-width: none; padding: 0; border: 0; margin: 0}

Lauren has a chart of distinct projected prices for a house over the next several years.  She must buy the house in one year and sell it in another, and she must do so at a loss.  She wants to minimize her financial loss.

For example, the house is valued at  over the next  years.  She can purchase the home in any year, but she must resell the house at a loss in one of the following years.  Her minimum loss would be incurred by purchasing in year  at  and reselling in year  at .

Find and print the minimum amount of money Lauren must lose if she buys the house and resells it within the next  years.

Note: It's guaranteed that a valid answer exists.

Function Description

Complete the minimumLoss function in the editor below.  It should return an integer that represents the minimum loss that can be achieved.

minimumLoss has the following parameter(s):

  • price: an array of integers that represent prices at each year

Input Format.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue} .MathJax_SVG_LineBox {display: table!important} .MathJax_SVG_LineBox span {display: table-cell!important; width: 10000em!important; min-width: 0; max-width: none; padding: 0; border: 0; margin: 0}

The first line contains an integer , the number of years of house data.
The second line contains  space-separated long integers describing each .

Constraints.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue} .MathJax_SVG_LineBox {display: table!important} .MathJax_SVG_LineBox span {display: table-cell!important; width: 10000em!important; min-width: 0; max-width: none; padding: 0; border: 0; margin: 0}

  • All the prices are distinct.
  • A valid answer exists.

Subtasks

  • for  of the maximum score.

Output Format.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue}

Print a single integer denoting the minimum amount of money Lauren must lose if she buys and resells the house within the next  years.

Sample Input 0.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue} .MathJax_SVG_LineBox {display: table!important} .MathJax_SVG_LineBox span {display: table-cell!important; width: 10000em!important; min-width: 0; max-width: none; padding: 0; border: 0; margin: 0} 35 10 3

Sample Output 0.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue} 2

Explanation 0.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue} .MathJax_SVG_LineBox {display: table!important} .MathJax_SVG_LineBox span {display: table-cell!important; width: 10000em!important; min-width: 0; max-width: none; padding: 0; border: 0; margin: 0}

Lauren buys the house in year  at  and sells it in year  at  for a minimal loss of .

Sample Input 1.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue} .MathJax_SVG_LineBox {display: table!important} .MathJax_SVG_LineBox span {display: table-cell!important; width: 10000em!important; min-width: 0; max-width: none; padding: 0; border: 0; margin: 0} 520 7 8 2 5

Sample Output 1.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue} 2

Explanation 1.MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: 0; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0; min-height: 0; border: 0; padding: 0; margin: 0} .MathJax_SVG * {transition: none; -webkit-transition: none; -moz-transition: none; -ms-transition: none; -o-transition: none} .mjx-svg-href {fill: blue; stroke: blue} .MathJax_SVG_LineBox {display: table!important} .MathJax_SVG_LineBox span {display: table-cell!important; width: 10000em!important; min-width: 0; max-width: none; padding: 0; border: 0; margin: 0}

Lauren buys the house in year  at  and sells it in year  at  for a minimal loss of .

Solution in java8

Approach 1.

import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        TreeSet<Long> values = new TreeSet<>();
        values.add(sc.nextLong());
        long min = Long.MAX_VALUE;
        for (int i = 1; i < n; i++) {
            long value = sc.nextLong();
            Long higherValue = values.higher(value);
            if (higherValue!=null) {
                min = Math.min(min, higherValue - value);
            }
            values.add(value);
        }
        System.out.println(min);
        sc.close();
    }
}

Approach 2.

import java.util.*;

public class MinimumLoss
{
    public static void main(String[] args)
    {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();

        long[] arr = new long[n];
        for(int i=0;i<n;i++)
        {
            arr[i] = sc.nextLong();
        }

        TreeSet<Long> tree = new TreeSet<>();
        tree.add(arr[n-1]);
        long min = Long.MAX_VALUE;
        for(int i=n-2;i>=0;i--)
        {
            if(tree.lower(arr[i])==null)
            {
                tree.add(arr[i]);
                continue;
            }
            long val = tree.lower(arr[i]);
            min = Math.min(min, arr[i]-val);
            tree.add(arr[i]);
        }

        System.out.println(min);
    }
}

Approach 3.

import java.io.*;
import java.util.*;

public class Solution 
{
    public static void main(String[] args) 
    {
        
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        long[] prices=new long[n];
        HashMap<Long,Integer>indices=new HashMap<>();

    
        for(int i=0;i<n;i++)
        {
            prices[i]=sc.nextLong();
            indices.put(prices[i],i);
        }

        Arrays.sort(prices);

        Long minimumLoss=Long.MAX_VALUE;

        
        for(int i=n-1;i>0;i--)
        {
            
            if(prices[i]-prices[i-1] < minimumLoss)
            {
                
                if(indices.get(prices[i]) < indices.get(prices[i-1]))
                {
                    minimumLoss = prices[i]-prices[i-1];
                }
            }
        }

        System.out.println(minimumLoss);

    }
}

Solution in python3

Approach 1.

n = int(input())
l = list(map(int, input().split()))
m = 10**17

d = {}
for i in range(len(l)):
    d[l[i]] = i
l.sort(reverse = True)

for i in range(len(l)-1):
    if d[l[i]] < d[l[i+1]] and l[i]-l[i+1] < m:
        m = l[i]-l[i+1]
print(m)

            

Approach 2.

n=int(input().strip())
numbers=list(map(int,input().strip().split()))
num=list(numbers)
num.sort()
minCost=10**10
for i in range(1,n):
    if(num[i]-num[i-1]<minCost) and (numbers.index(num[i])<numbers.index(num[i-1])):
        minCost=num[i]-num[i-1]
#return minCost
print(minCost)

Approach 3.

n =  int(input().strip())
numbers = list(map(int,input().strip().split()))

nums = list(numbers)
nums.sort()
minCost = 10**10
for i in range(1,n):
    if (nums[i]-nums[i-1] < minCost)  and (numbers.index(nums[i]) < numbers.index(nums[i-1])):
        minCost = nums[i]-nums[i-1]
print(minCost)

Solution in cpp

Approach 1.

#include<iostream>
#include<bits/stdc++.h>
#define ll long long
using namespace std;

int main(){

  ll i,n,j;
  cin>>n;
  ll *a = new ll[n];
  vector<pair<ll,ll>>v;
  for(i=0;i<n;i++){
      cin>>a[i];
      v.push_back(make_pair(a[i],i+1));
  }
  sort(v.begin(),v.end());
  ll mindiff = INT_MAX;
  for(i=1;i<n;i++){
      ll diff = v[i].first - v[i-1].first;
      if(v[i-1].second>v[i].second && diff<mindiff){
          mindiff = diff;
      }
  }
  cout<<mindiff;
  return 0;
  


}

Approach 2.

#include<cmath>
#include<set>
#include<cstdint>
#include<climits>
#include<tuple>
#include<cstdio>
#include<vector>
#include<iostream>
#include<algorithm>
#include<map>
#include<stack>
#include<queue>
#define long long long
using namespace std;


int main() {
    set<long> u;
    int n;
    cin>>n;
    long m = LONG_MAX;
    while(n--){
        long temp;
        cin>>temp;
        u.insert(temp);
        set<long>::iterator it;
        it = u.find(temp);
        if(++it != u.end()){
            m = min(*it - temp, m);
        }
    }
    cout << m;
}

Approach 3.

#include<iostream>
#include<climits>
#include<algorithm>
#include<vector>
using namespace std;
int main()
{
    int n;
    cin>>n;
    vector<pair<long,int>>prices;
    long long min=LONG_MAX;
    for(int i=0;i<n;i++)
    {
        long p;
        cin>>p;
        prices.push_back(make_pair(p,i));
    }
    sort(prices.begin(),prices.end());
    for(int i=0;i<n-1;i++)
    {
      if (min >(prices[i+1].first-prices[i].first) &&
          prices[i].second >prices[i+1].second )
          {
              min=prices[i+1].first-prices[i].first;
          }
    }

    
    cout<<min<<endl;

}

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