Hackerrank Ruby - Enumerable - each_with_index Solution
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Hackerrank Ruby - Enumerable - each_with_index Solution

Hackerrank Ruby - Enumerable - each_with_index Solution

In the previous challenge, we learned about each method being central to all of the methods provided by Enumerable class. One of such useful methods is each_with_index which allows you to iterate over items along with an index keeping count of the item.

For example,> colors = ['red', 'green', 'blue']> colors.each_with_index { |item, index| p "#{index}:#{item}" }"0:red""1:green""2:blue"

As you can note, the counting of items starts from 0.

In this challenge, your task is to complete the skip_animals method that takes an animals array and a skip integer and returns an array of all elements  except first skip number of items as shown in the example below.

For example,> skip_animals(['leopard', 'bear', 'fox', 'wolf'], 2)=> ["2:fox", "3:wolf"]

It is guaranteed that number of items in animals array is greater than the value of skip.

Solution in ruby

Approach 1.

def skip_animals(animals, skip)
    result = []
    animals.each_with_index { |a, i| result << "#{i}:#{a}" if i >= skip }

Approach 2.

def skip_animals(animals, skip)
    arr = []
    animals.each_with_index {|animal, i| arr.push("#{i}:#{animal}") if i >= skip}

Approach 3.

def skip_animals(animals, skip)
    rv = []
    animals.each_with_index do |a, i|
        rv << "#{i}:#{a}" if i >= skip

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