## Hackerrank - Smart Number Solution

In this challenge, the task is to debug the existing code to successfully execute all provided test files.

A number is called a *smart* number if it has an odd number of factors. Given some numbers, find whether they are smart numbers or not.

Debug the given function `is_smart_number`

to correctly check if a given number is a smart number.

Note: You can modify only *one* line in the given code and you cannot add or remove any new lines.

*To restore the original code in the editor, create a new buffer by clicking on the top left icon in the editor.*

**Input Format**

The first line of the input contains , the number of test cases.

The next lines contain one integer each.

**Constraints**

- , where is the integer.

**Output Format**

The output should consist of lines. In the line print *YES* if the integer has an odd number of factors, else print *NO*.

**Sample Input**

```
4
1
2
7
169
```

**Sample Output**

```
YES
NO
NO
YES
```

**Explanation**

The factors of 1 are just 1 itself.So the answer is YES. The factors of 2 are 1 and 2.It has even number of factors.The answer is NO. The factors of 7 are 1 and 7.It has even number of factors.The answer is NO. The factors of 169 are 1,13 and 169.It has odd number of factors.The answer is YES.

### Solution in Python

```
import math
def is_smart_number(num):
val = int(math.sqrt(num))
if num / val**2 == 1:
return True
return False
for _ in range(int(input())):
num = int(input())
ans = is_smart_number(num)
if ans:
print("YES")
else:
print("NO")
```