Leetcode - Determine if String Halves Are Alike Solution
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Leetcode - Determine if String Halves Are Alike Solution

You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.

Two strings are alike if they have the same number of vowels ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'). Notice that s contains uppercase and lowercase letters.

Return true if a and b are alike. Otherwise, return false.

Example 1:

Input: s = "book"
Output: true
Explanation: a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.

Example 2:

Input: s = "textbook"
Output: false
Explanation: a = "text" and b = "book". a has 1 vowel whereas b has 2. Therefore, they are not alike.
Notice that the vowel o is counted twice.

Example 3:

Input: s = "MerryChristmas"
Output: false

Example 4:

Input: s = "AbCdEfGh"
Output: true

Constraints:

  • 2 <= s.length <= 1000
  • s.length is even.
  • s consists of uppercase and lowercase letters.

Solution in Python

class Solution:
    @staticmethod
    def vowelsCount(s):
        return sum(1 for i in s if i in {"a","e","i","o","u"}) 
    def halvesAreAlike(self, s: str) -> bool:
        s = s.lower()
        midpoint = len(s)//2
        first_half = s[:midpoint]
        second_half = s[midpoint:]
        return self.vowelsCount(first_half)==self.vowelsCount(second_half)

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