# Leetcode - Flipping an Image Solution

Given an `n x n`

binary matrix `image`

, flip the image **horizontally**, then invert it, and return *the resulting image*.

To flip an image horizontally means that each row of the image is reversed.

- For example, flipping
`[1,1,0]`

horizontally results in`[0,1,1]`

.

To invert an image means that each `0`

is replaced by `1`

, and each `1`

is replaced by `0`

.

- For example, inverting
`[0,1,1]`

results in`[1,0,0]`

.

**Example 1:**

```
Input: image = [[1,1,0],[1,0,1],[0,0,0]]
Output: [[1,0,0],[0,1,0],[1,1,1]]
Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
```

**Example 2:**

```
Input: image = [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
```

**Constraints:**

`n == image.length`

`n == image[i].length`

`1 <= n <= 20`

`images[i][j]`

is either`0`

or`1`

.

## Solution in Python

```
class Solution:
def flipAndInvertImage(self, A: List[List[int]]) -> List[List[int]]:
return [list(map(lambda x:(x+1)%2, reversed(arr))) for arr in A]
```