## Leetcode - N-Repeated Element in Size 2N Array Solution

In a array `A`

of size `2N`

, there are `N+1`

unique elements, and exactly one of these elements is repeated `N`

times.

Return the element repeated `N`

times.

**Example 1:**

```
Input: [1,2,3,3]
Output: 3
```

**Example 2:**

```
Input: [2,1,2,5,3,2]
Output: 2
```

**Example 3:**

```
Input: [5,1,5,2,5,3,5,4]
Output: 5
```

**Note:**

`4 <= A.length <= 10000`

`0 <= A[i] < 10000`

`A.length`

is even

## Solution in Python

```
from collections import Counter
class Solution:
def repeatedNTimes(self, A: List[int]) -> int:
count = Counter(A)
return count.most_common()[0][0]
```