# Leetcode - Shuffle String Solution

Given a string `s`

and an integer array `indices`

of the **same length**.

The string `s`

will be shuffled such that the character at the `i`

position moves to ^{th}`indices[i]`

in the shuffled string.

Return *the shuffled string*.

**Example 1:**

```
Input: s = "codeleet", indices = [4,5,6,7,0,2,1,3]
Output: "leetcode"
Explanation: As shown, "codeleet" becomes "leetcode" after shuffling.
```

**Example 2:**

```
Input: s = "abc", indices = [0,1,2]
Output: "abc"
Explanation: After shuffling, each character remains in its position.
```

**Example 3:**

```
Input: s = "aiohn", indices = [3,1,4,2,0]
Output: "nihao"
```

**Example 4:**

```
Input: s = "aaiougrt", indices = [4,0,2,6,7,3,1,5]
Output: "arigatou"
```

**Example 5:**

```
Input: s = "art", indices = [1,0,2]
Output: "rat"
```

**Constraints:**

`s.length == indices.length == n`

`1 <= n <= 100`

`s`

contains only lower-case English letters.`0 <= indices[i] < n`

- All values of
`indices`

are unique (i.e.`indices`

is a permutation of the integers from`0`

to`n - 1`

).

Solution in Python

```
class Solution:
def restoreString(self, s: str, indices: List[int]) -> str:
return "".join(y for x,y in sorted(zip(indices,s)))
```