Leetcode - Reverse Integer Solution
Given a signed 32-bit integer x
, return x
with its digits reversed. If reversing x
causes the value to go outside the signed 32-bit integer range [-231, 231 - 1]
, then return 0
.
Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
Example 1:
Input: x = 123
Output: 321
Example 2:
Input: x = -123
Output: -321
Example 3:
Input: x = 120
Output: 21
Example 4:
Input: x = 0
Output: 0
Constraints:
-231 <= x <= 231 - 1
Solution in Python
class Solution:
def reverse(self, x: int) -> int:
if x<0:
x = int(str(x*-1)[::-1])*-1
else:
x = int(str(x)[::-1])
if x >= -2**31 and x <= 2**31-1:
return x
else:
return 0