Leetcode - Two Sum - Solution
1 min read

Leetcode - Two Sum - Solution

Leetcode - Two Sum - Solution

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

You can return the answer in any order.

Example 1:


nums = [2,7,11,15], target = 9 
Output: [0,1] 
Output: Because nums[0] + nums[1] == 9, we return [0, 1].

Example 2:


nums = [3,2,4], target = 6 
Output: [1,2]

Example 3:


nums = [3,3], target = 6 
Output: [0,1]


  • 2 <= nums.length <= 103
  • -109 <= nums[i] <= 109
  • -109 <= target <= 109
  • Only one valid answer exists.

Solution in Python

class Solution:
    def twoSum(self, nums: List[int], target: int) -> List[int]:
        seen = {}
        for index,number in enumerate(nums):
            second_number = target-number
            if second_number in seen:
                return [seen[second_number], index]
                seen[number] = index

Enjoying these posts? Subscribe for more

Adblocker detected! Please consider reading this notice.

We've detected that you are using AdBlock Plus or some other adblocking software which is preventing the page from fully loading.

That's okay. But without advertising-income, we can't keep making this site awesome.

We don't have any banner, Flash, animation, obnoxious sound, or popup ad. We do not implement these annoying types of ads!

We need money to operate the site, and almost all of it comes from our online advertising.

Please add thepoorcoder.com to your ad blocking whitelist or disable your adblocking software.