Leetcode - Unique Morse Code Words Solution
1 min read

Leetcode - Unique Morse Code Words Solution

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on.

For convenience, the full table for the 26 letters of the English alphabet is given below:


Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cab" can be written as "-.-..--...", (which is the concatenation "-.-." + ".-" + "-..."). We'll call such a concatenation, the transformation of a word.

Return the number of different transformations among all words we have.

Input: words = ["gin", "zen", "gig", "msg"]
Output: 2
The transformation of each word is:
"gin" -> "--...-."
"zen" -> "--...-."
"gig" -> "--...--."
"msg" -> "--...--."

There are 2 different transformations, "--...-." and "--...--.".


  • The length of words will be at most 100.
  • Each words[i] will have length in range [1, 12].
  • words[i] will only consist of lowercase letters.

Solution in Python

class Solution:
    def uniqueMorseRepresentations(self, words: List[str]) -> int:
        morse = [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
        alpha = "abcdefghijklmnopqrstuvwxyz"
        alpha = map(ord,alpha)
        table = dict(zip(alpha, morse))
        transformed = {word.translate(table) for word in words}
        return len(transformed)

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