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Python Re.start() & Re.end()

Python Re.start() & Re.end()

start() & end() These expressions return the indices of the start and end of the substring matched by the group.

Beeze Aal
Beeze Aal

start() & end()

These expressions return the indices of the start and end of the substring matched by the group.

Code

>>> import re
>>> m = re.search(r'\d+','1234')
>>> m.end()
4
>>> m.start()
0

Task
You are given a string .
Your task is to find the indices of the start and end of string  in .

Input Format

The first line contains the string .
The second line contains the string .

Constraints


Output Format

Print the tuple in this format: (start _index, end _index).
If no match is found, print (-1, -1).

Sample Input

aaadaa
aa

Sample Output

(0, 1)  
(1, 2)
(4, 5)

Solution in Python

import re
text, pattern = input(), input()
m= list(re.finditer("(?=(%s))"%pattern,text))
if not m:
    print((-1,-1))
for i in m:
    print((i.start(1),i.end(1)-1))