Leetcode - Backspace String Compare Solution

# Leetcode - Backspace String Compare Solution

Given two strings s and t, return true if they are equal when both are typed into empty text editors. '#' means a backspace character.

Note that after backspacing an empty text, the text will continue empty.

Example 1:

Input: s = "ab#c", t = "ad#c"
Output: true
Explanation: Both s and t become "ac".

Example 2:

Input: s = "ab##", t = "c#d#"
Output: true
Explanation: Both s and t become "".

Example 3:

Input: s = "a##c", t = "#a#c"
Output: true
Explanation: Both s and t become "c".

Example 4:

Input: s = "a#c", t = "b"
Output: false
Explanation: s becomes "c" while t becomes "b".

Constraints:

• 1 <= s.length, t.length <= 200
• s and t only contain lowercase letters and '#' characters.

Follow up: Can you solve it in O(n) time and O(1) space?

## Solution in Python

class Solution:
@staticmethod
def build(keys):
stack = []
for i in keys:
if i=="#":
if stack:
stack.pop()
else:
stack.append(i)
return stack
def backspaceCompare(self, S: str, T: str) -> bool:
return self.build(T)==self.build(S)